CLA-11-03 CLA - C Certified Associate Programmer Questions and Answers

• The program is a valid C program that can be compiled and run without errors.

• The variable i is declared as a char, which is an 8-bit signed integer type that can store val-ues from -128 to 127.

• The expression 20 + 020 + 0x20 evaluates to 68, because:

o 20 is a decimal literal with the value 20

o 020 is an octal literal with the value 16 (8^1 * 2 + 8^0 * 0)

o 0x20 is a hexadecimal literal with the value 32 (16^1 * 2 + 16^0 * 0)

o The + operator performs arithmetic addition on the operands and returns the sum

• The printf function prints the value of i as a decimal integer using the %d format specifier.

• The output of the program is 68.

1. A function fun is defined that takes a pointer to an integer t and returns t + 4.

2. The main function defines an array arr with the elements { 4, 3, 2, 1, 0 }.

3. It then calls fun with the argument arr - 3. Since arr points to the first element of the array, arr - 3 is actually pointing to 3 positions before the start of the array, which is out of bounds.

4. Inside fun, t + 4 would effectively be arr + 1 (arr - 3 + 4).

5. The returned pointer from fun (which is arr + 1) is assigned to ptr.

6. ptr[2] is then the same as arr[1 + 2] , which is arr[3]. The value at arr[3] is 1.

The program outputs 12.300000 because the printf function prints the value of f with a precision of 6 decimal places, which is the default precision for floating-point literals in C. The %f format specifier indicates that the argument is a floating-point value, and the space before it indicates that there should be a decimal point. The argument f is a float literal that represents 1e1 + 2e0 + 3e-1, which is equivalent to 1000000000 + 20000000 + 0.003 in decimal notation. Therefore, the output of the pro-gram is:

1e1 + 2e0 + 3e-1 = 1000000000 + 20000000 + 0.003 = 1230000000.003 = 123300000

The other options are incorrect because they either do not match the output of the program or do not use the correct format specifier for floating-point literals.

The program is a valid C program that can be compiled and run without errors. The program uses the argc and argv parameters of the main function, which are used to pass command-line arguments to the program. The argc parameter is an integer that stores the number of arguments, including the name of the program itself. The argv parameter is an array of strings that contains the arguments. The first element of the array, argv[0], is always the name of the program. The program declares an integer variable i and assigns it the value of 0. Then it prints the value of argv[i] as a string using the %s format specifier. Since i is 0, this is equivalent to printing argv[0], which is the name of the program. Therefore, the program outputs a predictable non-empty string, which is the name of the program. The exact name of the program may vary depending on how it is compiled and executed, but it will not be an empty string, an unpredictable string, or cause an execution failure. References = Command Line Arguments in C - GeeksforGeeks, Program Arguments (The GNU C Library), c - How to write a "argv" and "argc" - Stack Overflow

The declaration float **p; means that p is a pointer to a pointer to a float. It is used to declare a pointer that can point to another pointer, and that pointer, in turn, can point to a float.

In the fun function:

cCopy code

int fun(int i) { return i++; }

The post-increment operator i++ returns the current value of i and then increments it. So, fun(i) will return the current value of i (which is 1) and then increment i to 2.

In the main function:

cCopy code

int i = 1; i = fun(i); printf("%d", i);

Here, i is assigned the result of fun(i), which is 1. So, the program prints the value of i, which is 1.

Therefore, the correct answer is D. The program outputs 1.

The program is not a valid C program and cannot be compiled successfully. The reason is that the program uses the same name main for both a function and a variable, which is not allowed in C. The name main is a reserved keyword that denotes the entry point of the program, and it cannot be redefined or reused for any other purpose. Therefore, the compiler will report an error and the program will not run. References = C - main() function - Tutorialspoint, C Keywords - GeeksforGeeks, C Basic Syntax

The program is not a valid C program and cannot be compiled successfully. The reason is that the program has a syntax error: the sizeof operator expects an expression or a type name as its operand, but the program uses s.s, which is not a valid member of the structure str. The structure str has three members: i, j, and k, but not s. Therefore, the compiler will report an error and the program will not run. References = sizeof operator in C - GeeksforGeeks, C Program to Find the Size of int, float, double and char, Sizeof operator in C - Online Tutorials Library

The compilation fails because the program contains a syntax error. The identifier 1 is not a valid name for a variable, as it starts with a digit. Variable names in C must start with a letter or an under-score, and can contain letters, digits, or underscores. The compiler will report an error message such as error: expected identifier or '(' before numeric constant.

References = CLA – C Certified Associate Programmer Certification, C Essentials 1 - (Basics), C Varia-bles