Snowflake DAA-C01 Dumps Questions Answers

In Snowsight, managing dashboard layouts requires an understanding of how tiles (queries or visualizations) are stored versus how they are displayed. When an analyst wants to remove a tile from the visible dashboard grid without destroying the underlying query logic or historical configuration, the Unplace action is the correct functional choice.

When a tile is unplaced, it is removed from the dashboard's active layout but remains part of the dashboard's "library" of available content. This is a critical distinction from the Delete action (Option C), which permanently removes the tile and its associated SQL code from the dashboard object. Unplacing allows the analyst to "archive" the work temporarily. Because the tile still technically exists within the dashboard's metadata, any new data added to the underlying tables will still be processed by the query whenever the tile is eventually placed back onto the grid.

Evaluating the Options:

Option A (Show/Hide) is not a standard standalone command for dashboard tile management in Snowsight; visibility is typically managed through placement on the grid.

Option B (Duplicate) creates a second copy of the tile. While this preserves the data, it does not satisfy the requirement to "hide" the current tile; it actually adds more clutter to the dashboard.

Option C (Delete) is incorrect because the prompt specifies that the data and tile will need to be available in the future. Deleting would require the analyst to rewrite the SQL and reconfigure the visualization from scratch.

Option D is the 100% correct answer. Unplacing is the "soft-remove" feature of Snowsight. It preserves the tile in the "Unplaced Tiles" sidebar, allowing for quick restoration at a later date. This feature is essential for analysts who need to manage evolving reporting requirements where certain metrics may only be relevant seasonally or during specific business cycles.

To determine the correct result of the query, a Data Analyst must evaluate the nested functions according to standard SQL order of operations while correctly identifying how Snowflake handles NULL values in aggregate calculations.

Step 1: Evaluating AVG(GRADE)

The AVG() function calculates the arithmetic mean of the non-null values in a column. Based on the provided table data, the grades are: 4, 1, 2, 1, and 2. The sixth row contains a NULL grade. In Snowflake, as per ANSI SQL standards, aggregate functions ignore NULL values entirely. They are not treated as zeros, nor do they cause the function to return NULL (unless the entire column is null).

Sum of non-null values: $4 + 1 + 2 + 1 + 2 = 10$

Count of non-null values: $5$

Result: $10 / 5 = 2.0$

Step 2: Evaluating CEIL(..., 2)

The CEIL (or CEILING) function is typically used to return the smallest integer value that is greater than or equal to the input. However, Snowflake's CEIL function also supports an optional second argument for scale (precision).

The input is the result from the previous step: 2.0.

The scale argument is 2.

The function CEIL(2.0, 2) attempts to round the value up to the nearest value with two decimal places. Since 2.0 is already a whole number and has no fractional component beyond the specified scale, the ceiling remains 2.0.

Evaluating the Options:

Option A is incorrect as it represents a massive scaling error.

Option C and D are incorrect because they result from mathematical errors or incorrectly including the NULL row in the denominator (e.g., $10 / 6 = 1.66$, then rounded up).

Option B is the 100% correct answer. It accurately reflects the result of the AVG function ($2.0$) followed by the CEIL operation, which preserves the value as it is already at the target ceiling. This question tests precision in both mathematical logic and the technical nuances of Snowflake-specific SQL functions.

This scenario highlights the rules governing Shared Databases and Cross-Database Joins in Snowflake. When a user acquires data from the Snowflake Marketplace, it arrives in their account as a "Shared Database."

A critical restriction of shared databases is that they are read-only. Users (including Data Analysts and even AccountAdmins) cannot create new objects—such as tables, schemas, or views—directly inside a database created from a share. Therefore, Options A, C, and D are architecturally impossible because they all involve trying to write a new view into the ADDRESS_DATA database.

To combine the shared data with internal data (like the ORDERS table in GLOBAL_DWH), the Analyst must create the view in a database where they have CREATE VIEW privileges and that is writeable. Since GLOBAL_DWH is an internal database owned by the organization, it is the appropriate location to host the logic that joins local data with external enrichment data.

Evaluating the Options:

Option A and C are incorrect because you cannot create objects in a database created from a share.

Option D is incorrect because while IMPORTED_PRIVILEGES are necessary to view the data, they do not grant the ability to create objects within the share.

Option B is the 100% correct answer. By creating the view in the GLOBAL_DWH database (or any other local, non-shared database), the Analyst can successfully reference ADDRESS_DATA.OPENADDRESS and GLOBAL_DWH.PUBLIC.ORDERS in a single SQL statement, effectively creating an enriched data layer for the organization.